Question on: JAMB Mathematics - 1990
Three children shared a basket of mangoes in such a way that the first child took \(\frac{1}{4}\) of the mangoes and the second \(\frac{3}{4}\) of the remainder. What fraction of the mangoes did the third child take?
A
\(\frac{3}{16}\)
B
\(\frac{7}{16}\)
C
\(\frac{9}{16}\)
D
\(\frac{13}{16}\)
Ask EduPadi AI for a detailed answer
Correct Option: A
You can use any whole numbers (eg. 1. 2. 3) to represent all the mangoes in the basket.
If the first child takes \(\frac{1}{4}\) it will remain 1 - \(\frac{1}{4}\) = \(\frac{3}{4}\)
Next, the second child takes \(\frac{3}{4}\) of the remainder
which is \(\frac{3}{4}\) i.e. find \(\frac{3}{4}\) of \(\frac{3}{4}\)
= \(\frac{3}{4}\) x \(\frac{3}{4}\)
= \(\frac{9}{16}\)
the fraction remaining now = \(\frac{3}{4}\) - \(\frac{9}{16}\)
= \(\frac{12 - 9}{16}\)
= \(\frac{3}{16}\)
If the first child takes \(\frac{1}{4}\) it will remain 1 - \(\frac{1}{4}\) = \(\frac{3}{4}\)
Next, the second child takes \(\frac{3}{4}\) of the remainder
which is \(\frac{3}{4}\) i.e. find \(\frac{3}{4}\) of \(\frac{3}{4}\)
= \(\frac{3}{4}\) x \(\frac{3}{4}\)
= \(\frac{9}{16}\)
the fraction remaining now = \(\frac{3}{4}\) - \(\frac{9}{16}\)
= \(\frac{12 - 9}{16}\)
= \(\frac{3}{16}\)
Add your answer
Please share this, thanks!
No responses